That’s trivially true, as that last condition equals the claim:
but x^y > y^x, for y>x and x^y > y^x ^^^^^^^^^ ^^^^^^^^^
Another, minor, point: you write
> Why resort to the continuous domain to solve a problem n the discrete
and
> essentially we look for where the two 3d space surfaces intersect
Those two are in conflict with each other.
That’s trivially true, as that last condition equals the claim:
Also, if you leave out the and x^y > y^x part, that isn’t generally true because, for example 2⁴ = 4² and 1² < 2¹.Another, minor, point: you write
> Why resort to the continuous domain to solve a problem n the discrete
and
> essentially we look for where the two 3d space surfaces intersect
Those two are in conflict with each other.